Source code for toqito.matrix_props.is_commuting
"""Checks if the matrix is commuting."""
import numpy as np
[docs]
def is_commuting(mat_1: np.ndarray, mat_2: np.ndarray) -> bool:
r"""Determine if two linear operators commute with each other [@WikiComm].
For any pair of operators \(X, Y \in \text{L}(\mathcal{X})\), the
Lie bracket \(\left[X, Y\right] \in \text{L}(\mathcal{X})\) is defined
as
\[
\left[X, Y\right] = XY - YX.
\]
It holds that \(\left[X,Y\right]=0\) if and only if \(X\) and
\(Y\) commute (Section: Lie Brackets And Commutants from [@Watrous_2018_TQI]).
Examples:
Consider the following matrices:
\[
A = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix},
\quad \text{and} \quad
B = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}.
\]
It holds that \(AB=0\), however
\[
BA = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix} = A,
\]
and hence, do not commute.
```python exec="1" source="above"
import numpy as np
from toqito.matrix_props import is_commuting
mat_1 = np.array([[0, 1], [0, 0]])
mat_2 = np.array([[1, 0], [0, 0]])
print(is_commuting(mat_1, mat_2))
```
Consider the following pair of matrices:
\[
A = \begin{pmatrix}
1 & 0 & 0 \\
0 & 1 & 0 \\
1 & 0 & 2
\end{pmatrix} \quad \text{and} \quad
B = \begin{pmatrix}
2 & 4 & 0 \\
3 & 1 & 0 \\
-1 & -4 & 1
\end{pmatrix}.
\]
It may be verified that \(AB = BA = 0\), and therefore \(A\) and
\(B\) commute.
```python exec="1" source="above"
import numpy as np
from toqito.matrix_props import is_commuting
mat_1 = np.array([[1, 0, 0], [0, 1, 0], [1, 0, 2]])
mat_2 = np.array([[2, 4, 0], [3, 1, 0], [-1, -4, 1]])
print(is_commuting(mat_1, mat_2))
```
Args:
mat_1: First matrix to check.
mat_2: Second matrix to check.
Returns:
Return `True` if `mat_1` commutes with `mat_2` and False otherwise.
"""
return np.allclose(mat_1 @ mat_2 - mat_2 @ mat_1, 0)