Source code for toqito.matrix_props.is_commuting

"""Checks if the matrix is commuting."""

import numpy as np


[docs] def is_commuting(mat_1: np.ndarray, mat_2: np.ndarray) -> bool: r"""Determine if two linear operators commute with each other [@WikiComm]. For any pair of operators \(X, Y \in \text{L}(\mathcal{X})\), the Lie bracket \(\left[X, Y\right] \in \text{L}(\mathcal{X})\) is defined as \[ \left[X, Y\right] = XY - YX. \] It holds that \(\left[X,Y\right]=0\) if and only if \(X\) and \(Y\) commute (Section: Lie Brackets And Commutants from [@Watrous_2018_TQI]). Examples: Consider the following matrices: \[ A = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix}, \quad \text{and} \quad B = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix}. \] It holds that \(AB=0\), however \[ BA = \begin{pmatrix} 0 & 1 \\ 0 & 0 \end{pmatrix} = A, \] and hence, do not commute. ```python exec="1" source="above" import numpy as np from toqito.matrix_props import is_commuting mat_1 = np.array([[0, 1], [0, 0]]) mat_2 = np.array([[1, 0], [0, 0]]) print(is_commuting(mat_1, mat_2)) ``` Consider the following pair of matrices: \[ A = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 2 \end{pmatrix} \quad \text{and} \quad B = \begin{pmatrix} 2 & 4 & 0 \\ 3 & 1 & 0 \\ -1 & -4 & 1 \end{pmatrix}. \] It may be verified that \(AB = BA = 0\), and therefore \(A\) and \(B\) commute. ```python exec="1" source="above" import numpy as np from toqito.matrix_props import is_commuting mat_1 = np.array([[1, 0, 0], [0, 1, 0], [1, 0, 2]]) mat_2 = np.array([[2, 4, 0], [3, 1, 0], [-1, -4, 1]]) print(is_commuting(mat_1, mat_2)) ``` Args: mat_1: First matrix to check. mat_2: Second matrix to check. Returns: Return `True` if `mat_1` commutes with `mat_2` and False otherwise. """ return np.allclose(mat_1 @ mat_2 - mat_2 @ mat_1, 0)